Physics: A0.335 kg mass is attached to a spring and executes simple harmonic motion with a period of 0.38 s. the total energy of the system is 2.1 j. find the force constant of the spring. answer in units of n/m.

A0.335 kg mass is attached to a spring and executes

Ответ:

vdestiny858

10.01.2022

$k=91.54 \frac{N}{m}$

Explanation:

The angular speed is defined as the angle traveled in one revolution over the time taken to travel it, that is, the period. Therefore, it is given by:

$\omega=\frac{2\pi}{T}\\\omega=\frac{2\pi}{0.38s}\\\omega=16.53\frac{rad}{s}$

The angular frequency of the simple harmonic motion of the mass-spring system is defined as follows:

$\omega=\sqrt{\frac{k}{m}}$

Here, k is the spring's constant and m is the mass of the body attached to the spring. Solving for k:

$\omega^2=\frac{k}{m}\\k=m\omega^2\\k=0.335kg(16.53\frac{rad}{s})^2\\k=91.54 \frac{N}{m}$

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Ответ:

Kiona3815

15.06.2020

Physics

omg im in seventh grade but im not a 2003 kid

Explanation: I'm confused lol

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A0.335 kg mass is attached to a spring and executes simple harmonic motion with a period of 0.38 s. the total energy of the system is 2.1 j. find the force constant of the spring. answer in units of n/m.

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