A0.350 kg block at -27.5°c is added to 0.217 kg of water at 25.0°c. they come to equilibrium at 16.4°c. what is the specific heat of the block?

508 J/kg/C

Explanation:

Energy Lost by water = Energy gained by block

mcT = mcT [bolded is for water, italicised is for block]

(0.217)(4186)(25 - 16.4) = (0.350)(c)(16.4 + 27.5)

15.365c = 7811.9132

c = 508 J/kg/C (3 sf)

b. The potential energy decreases while the ball is going up.

Explanation:

Given that we have to neglect the air resistance.

As we know that acceleration due to gravity is in downward direction and it is equal to 10 m/s².

a)

If ball is going up then the velocity of the ball will decreases because the acceleration due to gravity is in opposite to the direction of velocity.That is why kinetic energy of the ball will decreases.

b)

As we know that when we are moving up then the our potential energy is also going to increase.That is why when ball is going to up then potential energy of the ball will increases.

c)

The kinetic energy will increase because the velocity of ball increase.

d)

If there is no any external  resistance force then the summation of kinetic and potential energy will be constant.

e)

When ball is coming to down then potential energy will decreases.

Note - Potential energy = m g h

 Kinetic energy = 0.5 m v²

Option B is correct.