A0.45-kilogram football traveling at a speed of 22 meters per second is caught by an 84-kilogram stationary receiver. if the football comes to rest in the receiver's arms, the magnitude of the impulse imparted to the receiver by the ball is

Impulse = Change in momentum.  
The ball was moving with a momentum of 0.45 * 22 = 9.9  
The ball comes to rest in the receivers arm; this means the ball's final velocity = 0. So mv2 = 0.45 * 0  
The magnitude of the impact is just the change in momentum. 9.9 - (0.45 * 0) = 9.9

The magnitude of the impulse imparted to the receiver by the ball is  –9.9 Kg•m/s

From the question given above, the following data were obtained:

Mass of ball (m) = 0.45 Kg

Initial velocity (u) = 22 m/s

Final velocity (v) = 0 m/s

Impulse (I) =?

The magnitude of the impulse imparted to the receiver by the ball can be obtained as follow:

Impulse = Change in momentum

I = m(v – u)

I = 0.45 (0 – 22)

I = 0.45 (–22)

I = –9.9 Kg•m/s

Thus, we can conclude that the magnitude of the impulse imparted to the receiver by the ball is  –9.9 Kg•m/s

Learn more: link

I think is b I think