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PrincessIndia
25.11.2019 •
Physics
A0.614mole sample of ideal gas at 12degree occupies a volume of 4.32.what is the pressure of the gas
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Ответ:
336.9520 atm
Explanation:
The Gas Equation is as follows;-
Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)
Given Parameters
Number of moles-0.614 mol
Temperature 12°C or 12+273.15 ie 285.15°F
Volume-4.32 L
Universal Gas Constant-8.314 J/mol·K
Pressure -?(in atm)
Plugging in all the values in the Gas Equation:-
Pressure=![\frac{0.614 × 8.314× 285.15}{4.32} atm](/tpl/images/0389/6251/8aa78.png)
Pressure=336.9520 atm
Ответ:
terd muffin is the correct answer