Physics: A1423-kg car is moving along a level highway with a speed of 26.4 m/s. the driver takes the foot off the accelerator and the car experiences a slowing force of 901-n over a distance of 106 m. determine the speed of the car after traveling this distance.

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A1423-kg car is moving along a level highway with - id14234177290, lilyrockstarmag

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12.01.2022

Final speed, v = 28.81 m/s

Explanation:

Given that,

Mass of the car, m = 1423 kg

Initial speed of the car, u = 26.4 m/s

Force experience by the car, F = 901 N

Distance, d = 106 m

To find,

The speed of the car after traveling this distance.

Solution,

The force experienced by a car is equal to the product of mass and acceleration.

F=ma

$a=\dfrac{F}{m}$

$a=\dfrac{901}{1423}$

$a=0.63\ m/s^2$

Let v is the final speed of the car. Using third equation of motion to find it as :

v^2-u^2=2ad

v^2=2ad+u^2

$v^2=2\times 0.63\times 106+(26.4)^2$

v = 28.81 m/s

So, the final speed of the car is 28.81 m/s.

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