Physics: A2,000-kg test car, traveling 60 m/s hits a brick wall. using motion pictures, the time involved is determined to be 0.050 s. what is the change in momentum of the car? a) +1.2 x 10^5 b)-1.2 x 10^5

A2,000-kg test car, traveling 60 m/s hits a brick - id200060161979, yaitzafigueroa

allytrujillo20oy0dib

10.03.2022

change in momentum of car is given as

$\Delta P = P_f - P_i$

here we have

$\Delta P = m(v_f - v_i)$

given that

m = 2000 kg

v_f = 0

v_i = 60 m/s

now we have

$\Delta P = 2000(0 - 60)$

$\Delta P = - 1.2 \times 10^5 kg m/s$

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carms12

16.02.2021

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Explanation:

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