A2.3kg box, starting from rest, is pushed up a ramp by a 10 n force parallel to the ramp. the ramp is 2.0 m long and tilted at 17 degrees. the speed of the box at the top of the ramp is 0.80m/s.how much work does the force do on the system? what is the change in the kinetic energy of the system? what is the change in the gravitational potential energy of the system? what is the change in the thermal energy of the system?

Part a)

Part b)

Part c)

Part d)

Explanation:

Part a)

Work done by the applied force is given by the formula

here we know that

Part b)

As we know that the box was at rest initially and then it is moving with speed 0.80 m/s

so here we can say

Part c)

Change in gravitational potential energy is given as

Part d)

Now by energy conservation law we can say that

Work done by external agent = change in kinetic energy + change in potential energy + thermal energy lost

so we have

350 N

Explanation:

Given

Mass of ball is

Speed of ball after rebound is

Time period for impulse

Impulse imparted in equal to the change in the momentum of object

Impulse is the product of average force and duration of application