A23 kg suitcase is being pulled with a constant speed by a handle that is at an angle of 29° above the horizontal. if the normal force exerted on the suitcase is 160 n, what is the force f applied to the handle?
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Ответ:
329.89N
Explanation:
Normal force is a force that is perpendicular to the horizontal surface. The normal force will therefore acts in the positive y direction.
To get the force F applied at the handle, we will resolve the force to the component of the normal force (y component)
The component of the force along the positive y axis (Fy) will be +Fsin(theta) where theta is 29°
Since both the normal force and the resolved force are acting in the same direction, Fy = normal force
Fsin(theta) = 160N
Fsin29°= 160N
F = 160/sin29°
F = 160/0.485
F = 329.89N
Therefore the force F applied to the handle is 329.89N
Ответ:
a) False
b) True
c) False
d) False
Reason: angle A and C are complementary instead of supplementary