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kingteron5870
28.09.2019 •
Physics
A55 g mouse runs out to the end of the 17 cm-long minute hand of a grandfather clock when the clock reads 10 minutes past the hour. what torque does the mouse's weight exert about the rotation axis of the clock hand?
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Ответ:
τ = rFsinθ
where
τ is torque
r is the length of minute hand
F is the force exerted by the mouse
θ is the angle
Every number interval in the clock has an angle of 30°. Because 10 minutes past the hour coincides with the number 10, θ = 30°*2 = 60°. For the force, it is simply the weight of the mouse which is
F = mg = (55g)*(1 kg/1000g)*(9.81 m/s²) = 0.53955 N
Substituting the rest of the values,
τ = (17cm)*(1 m/100 cm)*(0.53955 N)*(sin60°)
τ = 0.079 N·m
Ответ:
Because liquids flow freely, they take the shape of the container they are in, but have a definite volume. Like liquids, the shape of a gas changes with the container. This is because the atoms in a gas move rapidly and freely to fill any available space. Unlike liquids, the volume of a gas changes depending on the container it is in.
Hoped that help :)