Physics: A6.0 mw vertically polarized laser beam passes through a polarizing filter whose axis is 75° from vertical. what is the laser-beam power after passing through the filter?

Given,The initial position of the boat, d_i=(5i-2j+4k) mThe initial velocity of the boat, u=(4i+j-3k) m/sThe time period, t=8 sThe final velocity of the boat, v=(12i-7j+13k) m/sTo find:a) The position of the object after 8 sb) The acceleration of the object.Explanation:a)From the equation of motion, the total distance traveled by the object is given by,On substituting the known values,Thus the final position of the boat is,b)The acceleration of an object is given by,On substituting the known values,Final...

A6.0 mw vertically polarized laser beam passes

Ответ:

king3620

10.01.2022

Physics

I = 0.4019 m W

Explanation:

given,

Beam of light Intensity = 6.0 m W

angle made with the vertical = 75°

Power of the laser beam passing through filter = ?

using formula

I = I₀ cos²(θ)

I is the intensity required

I₀ is the initial intensity of light

I = I₀ cos²(θ)

I = 6 x cos²(75°)

I = 6 x 0.0669

I = 0.4019 m W

Laser beam power after passing through filter is equal to I = 0.4019 m W

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Ответ:

moneykingmarco079

12.11.2022

Physics

Given,

The initial position of the boat, d_i=(5i-2j+4k) m

The initial velocity of the boat, u=(4i+j-3k) m/s

The time period, t=8 s

The final velocity of the boat, v=(12i-7j+13k) m/s

To find:

a) The position of the object after 8 s

b) The acceleration of the object.

Explanation:

From the equation of motion, the total distance traveled by the object is given by,

$d=\frac{1}{2}(v+u)t$

On substituting the known values,

$\begin{gathered} d=\frac{1}{2}[(12\hat{i}-7\hat{j}+13\hat{k)}+(4\hat{i}+\hat{j}-3\hat{k})]8 \\ =4\times(16\hat{i}-6\hat{j}+10\hat{k}) \\ =(64\hat{i}-24\hat{j}+40\hat{k})\text{ m} \end{gathered}$

Thus the final position of the boat is,

$\begin{gathered} d_f=d_i+d \\ =\left(5\hat{i}-2\hat{j}+4\hat{k}\right)+(64\hat{i}-24\hat{j}+40\hat{k}) \\ =(69\hat{i}-26\hat{j}+44\hat{k})\text{ m} \end{gathered}$

The acceleration of an object is given by,

$a=\frac{v-u}{t}$

On substituting the known values,

$\begin{gathered} a=\frac{(12\hat{i}-7\hat{j}+13\hat{k)}-(4\hat{i}+\hat{j}-3\hat{k})}{8} \\ =\frac{8\hat{i}-8\hat{j}+16\hat{k}}{8} \\ =(\hat{i}-\hat{j}+2\hat{k})\text{ m/s}^2 \end{gathered}$

Final

a) Thus the position of the boat after 8 s is

$\begin{equation*} (69\hat{i}-26\hat{j}+44\hat{k})\text{ m} \end{equation*}$

The acceleration of the boat is

$\begin{equation*} (\hat{i}-\hat{j}+2\hat{k})\text{ m/s}^2 \end{equation*}$

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A6.0 mw vertically polarized laser beam passes through a polarizing filter whose axis is 75° from vertical. what is the laser-beam power after passing through the filter?

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