Physics: A75 kg skydiver and his 20g pet mouse jump from a plane. estimate their terminal speeds, assuming that they both fall in a prone position with limbs extended.

A75 kg skydiver and his 20g pet mouse jump from

ayoismeisalex

11.01.2022

Answer

given,

mass of the skydiver = 75 Kg

mass of pet = 20 g

to find the terminal speed of both the sky diver and the mouse

Using terminal speed formula

$v = \sqrt{\dfrac{4mg}{\rho\ A}}$

ρ is the density of the air

A is the area of mouse and skydiver

$v = \sqrt{\dfrac{4\times 75 \9.8}{1.23\times A}}$

Assuming area of Skydiver = 0.72 m²

and Area of mouse will be equal to = 0.0021 m²

now,

$v_{skydiver} = \sqrt{\dfrac{4\times 75\times 9.8}{1.2\times 0.72}}$

$v_{skydiver} =\sqrt{3402.777}$

$v_{skydiver} =58.33\ m/s$

$v_{mouse} = \sqrt{\dfrac{4\times 0.02\times 9.8}{1.2\times 0.0021}}$

$v_{mouse} =\sqrt{311.11}$

$v_{mouse} =17.63\ m/s$

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alexismoran1495

23.12.2022

I really believe it's (A) if it's not i'm honestly so sorry

Explanation:

I hope you feel better and find some friends to help you with it it's wrong

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