A80 ohms resistor, 0.2 h inductance and 0.1 mf capacitor are connected in series across a generator (60 hz, v rms=120 v). determine an impedance and current in the circuit.
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Ответ:
Impedance = 93.75 ohms
Current = 1.81 A
Explanation:
Resistance = R = 80 ohms
Inductance = L = 0.2 H
Inductive reactance = XL =
= ωL = (2πf) L
= 2 (3.14) (60)(0.2) = 75.398 Ohms
Capacitive reactance = 1 / ωC = 1/(2πf)C = 1 / [(2π)(60)(0.1 × 10⁻3)]
= 26.526 Ohms
Impedance = Z =![\sqrt{R^{2} + (X_{L} - X_{C})^{^{2}}} =](/tpl/images/0136/7334/3c9aa.png)
=
= 93.747 ohms
Voltage =
× 120 = 169.7056 V
Current = I = V ÷ R = (169.7056) ÷ 93,747 = 1.81 A
Ответ: