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elopezhilario6339
16.09.2019 •
Physics
Aball is dropped from the top of a building.after 2 seconds, it’s velocity is measured to be 19.6 m/s. calculate the acceleration for the dropped ball.
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Ответ:
Explanation:
The given data is as follows.
Initial velocity; u = 0, Final velocity; v = 19.6 m/s
time; t = 2 seconds
As the relation between initial velocity, final velocity and acceleration is as follows.
v = u + at
Hence, putting the given values into the above formula as follows.
v = u + at
19.6 m/s = 0 +![a \times 2 sec](/tpl/images/0232/0666/59ca9.png)
a = 9.8
Thus, we can conclude that acceleration of the dropped ball is 9.8
.
Ответ: