Abasketball player can leap upward 0.42 m. what is the magnitude of his initial velocity at the start of the leap? use g=9.81 m/s2.
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Ответ:
2×0.42×9.81=0²-vi²
8.2404=vi²
Vi=✓8.2404
Vi=2.87m/sec
Ответ:
Question 2; b
Question 3; b