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zafarm2oxgpmx
23.07.2019 •
Physics
Abat hits a 0.150 kg baseball for 0.0880s. the balls velocity changes from 41.0 m/s left to 37.0 m/s right. how much force was applied to the ball? unit= n
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Ответ:
F=ma
Where, F = applied force, m = mass (=0.15 kg), a = acceleration.
a= Δv/t, Δv= Change in velocity, t = time
Therefore
a = (41-37)/0.088 = 45.45 m/s^2
Then,
F = 0.15*45.45 = 6.82 N
Ответ:
There are no compounds on the list of choices you've provided.