Physics: Abody moving in the positive x direction passes the origin at time t=0.between t=0 and t=1second,the body has a constant speed of 27 meters per second. at t = 1 second, the body is given a constant acceleration of 6 meters per second squared in the negative x direction. the position x of the body at t = 11 seconds is

DExplanation: A magnetic current going through the wire...

Abody moving in the positive x direction passes

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ayowazzzgood

10.03.2022

Physics

In the first second of movement, the body's position at time relative to the origin is

$x=\left(27\dfrac{\rm m}{\rm s}\right)t$

so that after the first second, it will have undergone a displacement of

$x=\left(27\dfrac{\rm m}{\rm s}\right)(1\,\mathrm s)=27\,\mathrm m$

For every time , its position is then given by

$x=27\,\mathrm m+\left(27\dfrac{\rm m}{\rm s}\right)t+\dfrac12\left(-6\dfrac{\rm m}{\mathrm s^2}\right)t^2$

so that after t=11 seconds, it will have undergone a displacement of

$x=27\,\mathrm m+\left(27\dfrac{\rm m}{\rm s}\right)(11\,\mathrm s)+\dfrac12\left(-6\dfrac{\rm m}{\mathrm s^2}\right)(11\,\mathrm s)^2=\boxed{-39\,\mathrm m}$

so it ends up 39 m to the left of where it started (taking the right of the origin to be the positive direction).

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