Abox took five minutes to move. you did 3,150j - id31503895370, tatipop49

Question

Physics: Abox took five minutes to move. you did 3,150j of work in the process. how much power was required to move the box?

tatipop49 · Accepted Answer

To solve this problem it will be necessary to apply the linear motion kinematic equations plus the law of cosines and sines. This in order to determine the resulting speed and direction of movement. Through the law of cosines we know that the final magnitude of the velocity would be

R^2 = (4m/s)^2+(2m/s)^2 - 2(4m/s)(2m/s)cos(45)

R = 2.95m/s

With the speed found now we can identify the distance traveled, because the displacement was made during a period of 10 minutes at the speed previously found

$d = 2.95(m/s)(10min)(\frac{60s}{1min})$

d = 1770m

The direction of the displacement is found using the law of sines with the velocity triangle

$sin(\frac{\theta}{2}) = \frac{sin(45)}{2.9}$

Since the vehicle travels from south to north and from east to west then its deployment will be:

$\theta = 29\°$ north of due west

Abox took five minutes to move. you did 3,150j of work in the process. how much power was required to move the box?

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