Acar accelerates uniformly from rest and reaches a speed of 18 m/s in 13.8 s. the diameter of a tire is 60.8 cm. find the number of revolutions the tire makes during this motion, assuming no slipping.
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Ответ:
60.8cm is 0.608m, and now we can divide to work out the number of revolutions:
124.2/0.608 = 204.28 = 204 revolutions to 3sf (number of sf in the question assuming 18 is in fact 18.0, so the number you should give your answer to)
Ответ:
Why, EVERY ATOM of Element X has 38 of them in its nucleus !