Acar traveling at 27 m/s starts to decelerate steadily. it comes to a complete stop in 14 seconds. what is its acceleration?

You will need to use this formula:

V = Vo + a x t

V - Final velocity // If it comes to a complete stop,it will be 0 m/s.
Vo - Initial velocity = 27 m/s
a - Acceleration = ? m/s^2 // All units are in S.I
t - Time = 14 secs

So:

-> 0 = 27 + a x 14
-> 14a + 27 = 0
-> 14a = -27
-> a = -27/14
-> a = -1.928... m/s^2

Rounding to the nearest hundredth: -1.93 m/s^2.

The acceleration of the car is -1.93 m/s^2.

Kinetic  energy = 98 N

Explanation:

Given:

Mass = 5 kg

Height = 2 m

Find:

Kinetic  energy

Computation:

K(e) = P(e)

So,

P(e) = mgh

So,

K(e) = (5)(9.8)(2)

Kinetic  energy = 98 N