Acarnot engine whose low-temperature reservoir is at 19.4°c has an efficiency of 29.7%. by how much should the celsius temperature of the high-temperature reservoir be increased to increase the efficiency to 62.3%?
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Ответ:
The Temperature of the Hot reservoir should be increased by 359.86°C
Explanation:
A Carnot engine is a reversible engine, that means that it can work both as a heat engine and as a refrigerator, it can both use heat from a hot reservoir (part of which later must end up in a cold reservoir) to produce work, or use work to move heat from a cod to a hot reservoir.
The efficiency of a carnot engine working as a heat engine is given by:
were and are the Absolute temperatures of the hot and cold reservoir respectively.
To get the absolute temperature in K from the relative temperature in °C, we must add 273.15 K (the absolute temperature of the freezing point of water at atmospheric pressure)
Thus:
Now, if we know the Temperature of the cold reservoir, and the engine's efficiency, we can use that information to get as follows:
Now, that is the Temperature of the hot reservoir to begin with, but if we want a higher efficency, we need to increase until .
To find out what value has to reach, we repeat the same calculation as before, except now
So has increased from to , that means an increase in temperature of :
This increment of 359.86K is also an increment of 359.86°C, because increments are relative measures of temperature.
Ответ:
359.67°C or 359 K
Explanation:
Case I:
T2 = 19.4°C = 19.4 + 273 = 292.4 K
η = 29.7 % = 0.297
Let T1 be the temperature of hot reservoir.
By using the formula for the efficiency of Carnot's heat engine
T1 = 415.93 k
Case II:
T2 = 19.4°C = 19.4 + 273 = 292.4 K
η = 62.3 % = 0.623
Let T'1 be the temperature of hot reservoir.
By using the formula for the efficiency of Carnot's heat engine
T'1 = 775.6 k
Incraese in the temperature of hot reservoir
= T'1 - T1 = 775.6 - 415.93 = 359.67°C or 359 k
Ответ: