Physics: Acharged isolated metal sphere of diameter 15 cm has a potential of 8500 v relative to v = 0 at infinity. calculate the energy density in the electric field near the surface of the sphere.

Yes even if it s gas it still has something in it...

Acharged isolated metal sphere of diameter 15 cm

daisymae1172

13.03.2022

u = 0.057 J/m^3

Explanation:

Energy density near the surface of the sphere is given by the formula

$u = \frac{1}{2}\epsilon_0 E^2$

also for sphere surface we know that

$E = \frac{V}{R}$

R = radius of sphere

V = potential of the surface

now we have

$u = \frac{1}{2}\epsilon_0 (\frac{V^2}{R^2})$

now from the above formula we have

$u = \frac{1}{2}(8.85 \times 10^{-12})(\frac{8500^2}{0.075^2})$

u = 0.057 J/m^3

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