Physics: Acircular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) if the field is directed perpendicular to the plane of the loop and the magnetic flux through the loop is 8.60 10-3 t · m2, what is the strength of the magnetic field?

Acircular loop of radius 11.7 cm is placed in a uniform

Carlo1003

30.12.2021

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop, $\phi=8.6\times 10^{-3}\ T/m^2$

The magnetic flux linked through the loop is :

$\phi=B.A$

$\phi=BA\ cos\theta$

Here, $\theta=0$

$B=\dfrac{\phi}{A}$

$B=\dfrac{\phi}{\pi r^2}$

$B=\dfrac{8.6\times 10^{-3}}{\pi (0.117 )^2}$

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

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kkruvc

14.04.2023

22 N of force

Explanation:

Did the assignment already

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