Jharsh2300
26.01.2020 •
Physics
Aclosed pipe and an open pipe have their first overtones identical in frequency. their lengths are in the ratio?
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Ответ:
In that case the ratio is
2v/2L1 : 3v/4L2 = 4L2 : 3L1 .
Ответ:
α = -π/3 rad/s², θ = 1.5π rad = 0.75 rev
Explanation:
ω₀ = 30 rev/min(2π rad/rev / 60 s/min) = π rad/s
α = (ω₁ - ω₀)/t = (0 - π)/3 = -π/3 rad/s²
θ = (ω₁² - ω₀²) / 2α = (0² - π²) / 2(-π/3) = 3π/2 rad
3π/2 rad / 2π rad/rev = 0.75 rev