Acosmic ray electron moves at 7.45 â 106 m/s perpendicular to the earth's magnetic field at an altitude where field strength is 1.10 â 10â5 t. what is the radius (in m) of the circular path the electron follows?
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Ответ:
where q is the electron charge, v the electron speed, B the magnetic field intensity and
This force acts as centripetal force of the motion,
and by re-arranging this equation, we find the radius of the circular orbit, r:
Ответ:
Sledgehammer A has more momentum
Explanation:
Given:
Mass of Sledgehammer A = 3 Kg
Swing speed = 1.5 m/s
Mass of Sledgehammer B = 4 Kg
Swing speed = 0.9 m/s
Find:
More momentum
Computation:
Momentum = mv
Momentum sledgehammer A = 3 x 1.5
Momentum sledgehammer A = 4.5 kg⋅m/s
Momentum sledgehammer B = 4 x 0.9
Momentum sledgehammer B = 3.6 kg⋅m/s
Sledgehammer A has more momentum