Aglass bead charged to 3.7nc exerts an 7.0×10−4n repulsive electric force on a plastic bead 2.9cm away. what is the charge on the plastic bead?

The electrostatic force between the glass bead and the plastic bead is given by:

where
k is the Coulomb's constant
q1 is the charge of the glass bead
q2 is the charge of the plastic bead
r is the separation between the two beads

In this problem,  and , and since we know the force, , we can rearrange the equation to find q2, the charge of the plastic bead:

The charge on the plastic bead is 17.68 nC

Data obtained from the question Charge on glass bead (q₁) = 3.7 nC = 3.7×10¯⁹ CForce (F) = 7×10¯⁴ NDistance apart (r) = 2.9 cm = 2.9 / 100 = 0.029 mElectrical constant (K) = 9×10⁹ Nm²/C²Charge on plastic bead (q₂) =? How to determine the charge on the plastic bead

F = Kq₁q₂ / r²

7×10¯⁴ = (9×10⁹ × 3.7×10¯⁹ × q₂) / (0.029)²

Cross multiply

9×10⁹ × 3.7×10¯⁹ × q₂ = 7×10¯⁴ × (0.029)²

Divide both side by 9×10⁹ × 3.7×10¯⁹

q₂ = [7×10¯⁴ × (0.029)²] / (9×10⁹ × 3.7×10¯⁹)

q₂ = 17.68×10¯⁹ C

q₂ = 17.68 nC

Learn more about force on charges:

link

The answer is B, W, E, Q, K

Explanation:

I took the test, hope this helps :)