Physics: Aheavy steel ball is hung from a cord to make a pendulum. the ball is pulled to the side so that the cord makes a 5 ∘ angle with the vertical. holding the ball in place takes a force of 40 n . if the ball is pulled farther to the side so that the cord makes a 10 ∘ angle, what force is required to hold the ball?

it’s marble 4Explanation:I took the test and it was right...

Aheavy steel ball is hung from a cord to make a

kristinmonkey

15.01.2022

The required force is calculated as 79.69 N

Solution:

As per the question:

Angle, $\theta = 5^{\circ}$

Force, F = 40 N

The angle after the ball is being pulled, $\theta' = 10^{\circ}$

Now,

To calculate the required force:

The tension in the string can be calculated by considering the vertical component:

$F = Tsin\theta$

where

T = Tension in the cord

Now,

$T = \frac{F}{sin\theta} = \frac{40}{sin5^{\circ}} = 458.94\ N$

Now, after the cord is being pulled, the force exerted is given by:

$F' = Tsin\theta' = 458.94\times sin10^{\circ} = 79.69\ N$

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