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kellysimkin6196
06.12.2019 •
Physics
Air contained in a rigid, insulated tank fitted with a paddle wheel, initially at 300 k, 2 bar, and a volume of 3 m3, is stirred until its temperature is 600 k. assuming the ideal gas model for the air, and ignoring kinetic and potential energy, determine : (a) the final pressure, in bar. (b) the work, in kj. (c) the amount of entropy produced, in kj/k.
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Ответ:
a)P₂ =4 bar
b)W= - 1482.48 KJ
It means that work done on the system.
c)S₂ - S₁ = 3.42 KJ/K
Explanation:
Given that
T₁ = 300 K ,V₁ = 3 m³ ,P₁=2 bar
T₂ = 600 K ,V₂=V₁ 3 m³
Given that tank is rigid and insulated.It means that volume of the gas will remain constant.
Lets take the final pressure = P₂
For ideal gas P V = m R T
P₂ =4 bar
Internal energy
ΔU = m Cv ΔT
Cv=0.71 KJ/kg.k for air
m= 6.96 kg
ΔU= 6.96 x 0.71 x (600 - 300)
ΔU=1482.48 KJ
From first law
Q= ΔU + W
Q= 0 Insulated
W = - ΔU
W= - 1482.48 KJ
It means that work done on the system.
Change in the entropy
S₂ - S₁ = 3.42 KJ/K
Ответ:
Explanation:
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