Amass suspended by a spring stretches an additional 4 ccm when an additional 10 gram mass is attached to it. what is the value of the spring constant k, in si units

2.45 N/m

Explanation:

We can find the spring constant by using Hooke's law:

where

F is the force applied to the spring

k is the spring constant

x is the stretching of the spring

Here, the force applied is the weight of the mass hanged on the spring. The mass is

m = 10 g = 0.010 kg

So the weight is

while the stretching is

x = 4 cm = 0.04 m

So the spring constant is

Explanation:

Remark

This is a momentum question. Both cars are sitting still (v1 and v2 are both 0) to start with). When the spring is sprung), they both move but in opposite directions.

Let us say that v4 is minus.

Equation

0 = m3*v3 - m4* v4

Givens

m3 = 1750 kg

m4 = 1000 kg

v3 = 4 m/s

Solution

m3*4m/s - m4*x = 0

1750 * 4 - 1000*x = 0

1750 * 4 = 1000x

7000 = 1000 x

7000/1000 = x

x = 7 m/s