Amissile is moving 1350 m/s at a 25 degree angle. it needs to hit a target 23,500 m away in a 55 degree direction in 10.20 seconds. what is the direction of its final velocity?
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Ответ:
Or
Explanation:
We know that the initial speed is:
1350 m/s at a 25 degree angle
And the final position after 10.20 sec is:
23,500 m away in a 55 degree direction
In this problem we have:
Final position in x:
Where
is the initial velocity in x
So:
We solve for![a_x](/tpl/images/0156/7094/508a4.png)
X component of velocity
Where
is the acceleration in the direction x
And![a_x=19.21\ m/s^2](/tpl/images/0156/7094/2b02f.png)
Therefore:
Final position in y:
Where
is the initial velocity in y
So:
We solve for![a_y](/tpl/images/0156/7094/6a8c3.png)
Y component of velocity
Where
is the acceleration in the direction y
And![a_y=258.18\ m/s^2](/tpl/images/0156/7094/5900c.png)
Therefore:
Note then that the final velocity V is a two component vector
The magnitude of the final speed is:
And the angle that forms with the x axis is:
Ответ:
The answer is c. Both use the twelve tables to protect citizens rights