An aerophone is an instrument that causes to vibrate, thus creating sound waves

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Ответ:

sallonquarts

05.07.2022

Physics

30.34 m

Explanation:

Given

launch angle $=51.7^{\circ}$

Initial velocity u=31.9 m/s

Position of net = 39.1 m

We know equation of trajectory of a projectile is

$y=x\tan \theta -\frac{gx^2}{2u^2(\cos \theta )^2}$

$y=39.1\times \tan 51.7-\frac{9.8\times 39.1^2}{2\times 31.9^2\times (cos51.7)^2}$

$y=49.509-\frac{9.8\times 1.502}{2\times 0.384}$

$y=49.509-\frac{14.719}{0.768}$

y=49.509-19.165=30.343 m

Therefore Net should be placed 30.34 m above ground

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