An air capacitor is made from two flat parallel plates 1.50 mm apart. the magnitude of charge on each plate is 0.0180 μc when the potential difference is 200 v. when the charge is 0.0180 μc, what total energy is stored?

The energy stored in a capacitor is given by

where V is the voltage applied, and  is the capacitance.

Substituting  into the first equation, we can rewrite the energy stored as

And since we know the charge,  and the voltage difference, V=200 V, we find the energy stored:

Hello there, the correct answer is:

B.