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zitterkoph
23.03.2020 •
Physics
An archer draws his compound bow and shoots an arrow. The 23 g arrow leaves the bow with a velocity of 88 m/s. The power stroke of the bow is 57 cm; that is, the bowstring exerts force on the arrow through a displacement of 57 cm. The peak draw weight of the bow is 312 N. (This is the maximum force that the archer has to exert on the bowstring.)
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Ответ:
156.24N
Explanation:
From the data above;
Mass = 23g = 0.023kg
V = 88m/s
Kinetic energy = ½mv²
K.e = ½* 0.023 * 88²
K.E = 89.056J
The force required to accelerate the arrow to that speed and energy in 0.57m
Using equation of motion;
V² = U² + 2as
But U =0
V² = 2as
a = v²/2s
a = 88² / (2*0.57)
a = 6792.98m/s²
The force (F) that accelerates the arrow with that velocity = ?
F = M*a
F = 0.023 * 6792.98
F = 156.24N
Ответ:
physics is the study of the laws of gravity
Explanation: