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daniellacalles
19.04.2021 •
Physics
An electric iron consumes energy at a rate of 840 W when heating is at the maximum rate and 360 W when the heating is at the minimum. The voltage is 220 V. What are the current and the resistance in each case?
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Ответ:
See Explanation
Explanation:
We know that;
P= IV
Where;
P = power
I= current
V = voltage
Here, we have a voltage of 220V
Hence, for maximum rate;
P= IV
I = P/V
P = 840 W
V= 220 V
I= 840 W/220 V
I= 3.8 A
V = IR
R = V/I
R = 220/3.8
R = 57.9 Ω
For minimum heating;
P= 360 W
V= 220 V
I = P/V
I = 360 W/220V
I= 1.6 A
V= IR
R = V/I
R = 220 V/1.6 A
R = 137.5 Ω
Ответ:
3
Explanation:
Im not that sure but I think its close... [srr]