LlayahHarbin
15.07.2019 •
Physics
An engine performs 6400 j of work on a motorbike the motorbike and the rider have a combined mass of 200 kg if the bike started at rest what is the speed of the bike after the work is performed
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Ответ:
The speed of the bike after the work is performed is 8 m/s
Data obtained from the question Energy (E) = 6400 JMass (m) = 200 KgVelocity (v) =?How to determine the velocityEnergy, mass and velocity of an object is related according to the following equation:
Energy (E) = ½ × mass (m) × Square velocity (v²)
E = ½mv²
With the above formula, we can obtain the velocity of the bike as follow:
E = ½mv²
6400 = ½ × 200 × v²
6400 = 100 × v²
Divide both side by 100
v² = 6400 / 100
v² = 64
Take the square root of both side
v = √64
v = 8 m/s
Learn more about energy:
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Ответ:
The work done by the engine is converted into kinetic energy of the motorbike+rider system:
where
W=6400 J is the work
m=200 kg is the mass of the system
v is the speed acquired by the motorbike
Rearranging the equation and substituting the numbers in, we find
Ответ: