Physics: An exoplanet is in an elliptical orbit around a distant star. at its closest approach, the exoplanet is 0.540 au from the star and has a speed of 54.0 km/s. when the exoplanet is at its farthest distance from the star of 41.0 au, what is its speed (in km/s)? (1 au is the average distance from the earth to the sun and is equal to 1.496 ✕ 1011 m. you may assume that other planets and smaller objects in the star system exert negligible forces on the exoplanet.)

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An exoplanet is in an elliptical orbit around

Ответ:

sippincoronas

12.01.2022

Physics

0.71121 km/s

Explanation:

v_1 = Velocity of planet initially = 54 km/s

r_1 = Distance from star = 0.54 AU

v_2 = Final velocity of planet

r_2 = Final distance from star = 41 AU

As the angular momentum of the system is conserved

$mv_1r_1=mv_2r_2\\\Rightarrow v_1r_1=v_2r_2\\\Rightarrow v_2=\frac{v_1r_1}{r_2}\\\Rightarrow v_2=\frac{54\times 0.54}{41}\\\Rightarrow v_2=0.71121\ km/s$

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.

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