Physics: An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.3 times the mass of the other. if 8800 j is released in the explosion, all of which goes into the kinetic energy of the two pieces, how much kinetic energy does each piece acquire?

An internal explosion breaks an object, initially

201889992

30.12.2021

k_2 =3826.08 J

K_1 = 4973.91 J

Explanation:

from conservation of momentum principle

0 = m_1v_1+m_2v_2

we know that kinetic energy is given as

$k_1 = \frac{1}{2} m_1v_1^2$

$k_2 = \frac{1}{2} m_2v_2^2$

we have v_1 =-1.3v_2 , m_2 = 1.3m_1

therefore $k_1 =\frac{1}{2} (\frac{m_2}{1.3})(-1.3v_2)^2 = 1.3k_2$

now

k_1+k_2 = 8800

1.3k_2 +k_2 =8800

k_2 =3826.08 J

K_1 = 4973.91 J

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naomicervero

14.12.2021

Right answers : 10

Wrong answers : 2

Ratio of right answers to wrong answers :

$\frac{10}{2} =\frac{5}{1}$

→ B

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