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issaaamiaaa15
25.09.2019 •
Physics
An object hits a wall and bounces back with half of its original speed. what is the ratio of the initial kinetic energy to the final kinetic energy?
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Ответ:
Kinetic energy (KE) is given as
We write the initial kinetic energy is KE.1 =(1/2)mu^2
When speed is halved, speed will be u/2,
then final kinetic energy will be KE.2 = ( 1/2)m[u/2]^2 = (1/8)mu^2
Now,ON SOLVING K,E1 /K.E2, WE GET = 4:1
Ответ: