An object of inertia 0.5kg is hung from a spring, and causes it to extend 5cm. in an elevator accelerating downward at 2 m/s^2 , how far will the spring extend if the same object is suspended from it? draw the free body diagrams for both the accelerating and non-accelerating situations.
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Ответ:
3.98cm
Explanation:
given data
mass of object
=0.5kg
intial extension=5 cm
elevator acceleration=2 m/
From FBD of intial position
Kx=mg
K=
k=98.1 N/m
From FBD of second situation
mg-k
=ma
k
=m(g-a)
Ответ:
I think 4b\c 60 divers by 15 is 4 so 4 feet