Anet force of 50 n is applied to a 10 kg cart that is already moving at 3 m/s. the final velocity of the cart was 8 m/s. for how long was the force applied

1 second

Explanation:

Assuming that the force is in the same direction as speed we can do the graphic.

Draw the forces present on the problem (weight and the net force).Newton's second law. The summation of the forces is equal to the product between mass and aceleration.Plan the equation on x direction (because the mass is moving on that way). The result would be: From that equation we know that the aceleration is 5m/s2.Also, we know (because it is a uniform line movement) that the aceleration is related with the speed. Clearing the equation: And replacing: So, the force is applied for 1 second.

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction