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Juliette9525
03.02.2020 •
Physics
Apassenger on a moving train walks at a speed of 1.40 m/s due north relative to the train. the train is traveling at 3.5 m/s due east relative to the ground. what are the magnitude and direction of the velocity of the passenger relative to the ground
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Ответ:
v= 4.9 m/s in east direction ( or v=4.9 m/s * i )
Explanation:
Since the passenger moves along the train ( in the north direction relative to the train) then if the train is traveling east relative to the ground , the passenger will also travel to the east relative to the ground .
Then the magnitude of the velocity will be
v= 1.40 m/S + 3.5 m/s = 4.9 m/s
v= 4.9 m/s
and the direction will be east ( if the x axis represents east direction and y-axis the north direction , then the velocity vector will be v=4.9 m/s * i )
Ответ:
f
Explanation: