Aproton and an electron are both accelerated to the same final speed. if λp s the de broglie wavelength of the proton and e is the de broglie wavelength of the electron, then 5, d) not enough data to answer this question

Explanation:

The relation between the de Broglie wavelength and the momentum of the particle is given by

where, m is the mas of the particle and v be the velocity of the particle and h be the Plank's constant.  

So, the de broglie wavelength of proton is given by

.... (1)

The de broglie wavelength of electron is given by

.... (2)

Divide equation (2) by equation (1), we get

As the mass of proton is much more than the mass of electron, so the de broglie wavelength of electron is more than the de Broglie wavelength of proton.

The intensity level of sound in the bedroom is 80dB

Explanation:

Intensity of lawn mower at r=1m is 100dB

Beta1= 10dBlog(I1/Io)

100dB= 10dB log(I1/Io)

10^10= I1/Io

I1= Io(10^10)

10^12)×(10^10)= I1

I1=10^-2w/m^2

Intensity of lawn mower at r=20m

I2/I1=(r1/r2)^2 =(1/20)^2

I2= I1(1/400)

I2=2.5×10^-3W_m^2

Intensity of 4 lown mowers at 20m fro. Window

= 10dBlog(4I2/Io)

= 10^-4/10^-12

=80dB