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sujeyribetanco2216
14.09.2019 •
Physics
Aquantity of 14.1 cm^3 of water at 8.4°c is placed in a freezer compartment and allowed to freeze to solid ice at -7.2°c. how many joules of energy must be withdrawn from the water by the refrigerator?
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Ответ:
920.31 J
Explanation:
Given
Volume of water (V)![=14.1 cm^3](/tpl/images/0231/0450/5067d.png)
mass(m)![=\rho \times V=1000\times 14.1\times 10^{-6}=14.1 gm](/tpl/images/0231/0450/813d2.png)
Temperature![=8.4^{\circ} C](/tpl/images/0231/0450/cb40f.png)
Final Temperature![=-7.2 ^{\circ}C](/tpl/images/0231/0450/c66b3.png)
specific heat of water(c)![=4.184 J/g-^{\circ}C](/tpl/images/0231/0450/232c1.png)
Therefore heat required to removed is
Ответ:
3.57N
Explanation:
given
Speed of rotation, N = 1300 rpm
diameter, d = 35 cm, so that
radius, r = 17.5 cm = 0.175 m
mass of drop = 1.1 g = 1.1*10^-3 kg
Angular speed of water, ω = 2πN/60
ω = 2π*1300/60
ω = 8169.2/60
ω = 136.15 rad/s
apparent weight will be gotten by
W(a) = mω²r
W(a) = 1.1*10^-3 * 136.15² * 0.175
W(a) = 1.1*10^-3 * 18536.82 * 0.175
W(a) = 3.57 N
Therefore, the apparent weight of 1.1 g of water is 3.57 N