Arocket accelerates upward from rest at a rate of 5 m/s^2. at a height of 1000m, the engines burn out and it coasts the rest of the way with an acceleration of -9.8 m/s^2. a. what is the rocket's velocity at burnout (h=1000m) in meters/second? b. for how many seconds did the rocket engine burn? c. what is the rocket's maximum altitude?

Explanation:

Given

acceleration of rocket(a)

At h=1000 m rocket burn out

(b) time to reach v=100 m/s

v=u+at

(c)Rocket maximum altitude

here u=100 m/s

v=0

[tex]s=510.204

Therefore maximum altitude=510.204+1000=1510.204 m

Explanation:

The force acting on an object can be found by using the formula

From the question

mass = 45 kg

acceleration = 1.5 m/s²

We have

Force = 45 × 1.5

We have the final answer as

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