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ianmartin6080
18.01.2020 •
Physics
Asample of wood has a heat of combustion of 3.29 kj/g. what quantity of the wood must be burned to heat 250. g of water from 18°c to 85°c? once again, the specific heat capacity of water is 4.18 j/°c·g.
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Ответ:
The quantity of wood that must be burned= 21.28 g
Explanation:
Heat produce by the wood = heat absorbed by the water
Q₁ = Q₂ Equation 1
Where Q₁ and Q₂ are heat produce by the wood and heat absorbed by the water respectively.
Q₁ = c₁m₁ Equation 2
Q₂ = c₂m₂(T₂-T₁) Equation 3
Substituting equation 2 and 3 into equation 1
c₁m₁ = c₂m₂(T₂-T₁) Equation 4
making m₁ the subject of the equation,
m₁ = c₂m₂(T₂-T₁)/c₁ Equation 5
Where c₁ = heat of combustion of the wood, c₂ = specific heat capacity of water, m₁ = mass of the wood, m₂ = mass of water, T₁ = initial temperature, T₂ = final Temperature.
Given: c₁ = 3.29 kJ/g = 3290 J/g, c₂ = 4.18 J/g.°C, m₂ = 250 g, T₂ = 85 °C, T₁ = 18 °C
Substituting these values into equation 4,
m₂ = 4.18×250(85-18)/3290
m₂ = 70015/3290
m₂ = 21.28 g
Thus the quantity of wood that must be burned= 21.28 g
Ответ:
si no lo entiendes dile a tu profe que te explique, de nad ;)
Explanation: