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justachelseafan
19.01.2020 •
Physics
Asoap bubble has a diameter of 4mm .cakculate the pressure inside it if the atmospheric pressure outside is 10^5nm^2 . the surface tension of soap =2.8* 10^-2n/m
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Ответ:
Explanation:
The formula for determining the pressure inside a soap bubble is expressed as
Pi - Po = 4T/r
Where
Pi represents the pressure inside the bubble.
Po represents the pressure outside the bubble or the atmospheric pressure.
T represents the surface tension.
r represents radius of the bubble.
From the information given,
Diameter of bubble = 4mm. Converting to meters, it becomes
4/1000 = 0.004m
Radius of bubble = 0.004/2 = 0.002m
T = 2.8 × 10^-2N/m
Po = 1 × 10^5Nm^-2
Therefore,
Pi - 10^5 = 4 × 2.8 × 10^ -2/0.004
Pi - 10^5 = 28
Pi = 28 + 1 × 10^5 = 100028Nm^-2
Ответ:
Explanation:
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