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breonnabyers
08.07.2019 •
Physics
Aspring of equilibrium length l1 and spring constant k1 hangs from the ceiling. mass m1 is suspended from its lower end. then a second spring, with equilibrium length l2 and spring constant k2, is hung from the bottom of m1. mass m2 is suspended from this second spring. how far is m2 below the ceiling?
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Ответ:
The total distance of m₂ from the ceiling is![d = L_1 + L_2 + \frac{g(m_1 + m_2)}{k_1} + \frac{m_2g}{k_2}](/tpl/images/0066/9854/635a6.png)
The given parameters;
equilibrium of length of the spring, = L₁spring constant, = K₁mass on the spring = m₁length of the first spring, = L₂spring constant = K₂mass on the second spring, = m₂The extension of the first spring due to mass m₁ and m₂ is calculated as;
The extension of the second spring due to mass (m₂) is calculated as;
The total distance of m₂ from the ceiling is calculated as follows;
Thus, the total distance of m₂ from the ceiling is![d = L_1 + L_2 + \frac{g(m_1 + m_2)}{k_1} + \frac{m_2g}{k_2}](/tpl/images/0066/9854/635a6.png)
Learn more here:link
Ответ:
Explanation:
For first spring the total extension is given as
here net force is due to weight of both masses
so extension of first spring is
now similarly the extension in second spring is only due to the weight of mass m2
so here we will have
so the total distance from the ceiling for mass m2 is given as
Ответ:
b) to produce electrical charges;
Explanation:
Electrical generators are used in a circuit to produce electrical charges. The flow of these charges actually produces electrical energy in a circuit which is needed and essential to power devices and gadgets.
A generator uses mechanical energy through the movement of its parts to produce electrical energy. The flow of electrons streams produces the electrical energy which helps to produce power.
A generator works on the basis of electromagnetic induction using the movement of electric charges.