Assume a hydro power plant with 85% efficiency and 30m head. it is measured that 60 kg of water passes through the turbine in 1 s. what is the output electrical power of this power plant?
a) less than 1 kw
b) between 1 kw and 10 kw
c) more than 10 kw
show calculations!

The potential energy of each kg of water, before it falls, is

   (M G H) = (1kg) (9.8 m/s²) x (30 m) = 294 joules

The potential energy lost by 60 kg of water pouring through is

      (60 x 294) = 17,640 joules

The power output of the plant is

         (17,640 joules/sec) x (85%) = 14,994 watts
                                               = almost but not quite 15 kW.

(If you used 10 for gravity, it would come out to 15.3 kW)

V=v0+at

V0=0

So v=at.

And v=14m/s, t=6.0s.

So a=v/t, a=14/6m/s^2

a=2.333333m/s^2