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jocelyn7575
10.03.2020 •
Physics
Assuming 95.0% efficiency for the conversion of electrical power by the motor, what current must the 12.0-V batteries of a 708-kg electric car be able to supply to do the following?
(a) accelerate from rest to 25.0 m/s in 1.00 min
1 (answer in Amps)
(b) climb a 200-m high hill in 2.00 min at a constant 25.0 m/s speed while exerting 423 N of force to overcome air resistance and friction
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Ответ:
(a). The current is 323.4 A.
(b). The current is 1942 A.
Explanation:
Given that,
Efficiency = 95.0 %
Voltage = 12.0 V
Mass of electric car= 708 Kg
Height = 200 m
We need to calculate the change in kinetic energy
Using formula of kinetic energy
Put the value into the formula
We need to calculate the output power
Using formula of power
We need to calculate the current
Using formula of electric power
Put the value into the formula
The current is 323.4 A.
(b). We need to calculate the distance
Put the value into the formula
We need to calculate the force
Using formula of force
Put the value into the formula
We need to calculate the power
Using formula of power
Put the value into the formula
We need to calculate the current
Using formula of current
Put the value into the formula
The current is 1942 A.
Hence, (a). The current is 323.4 A.
(b). The current is 1942 A.
Ответ: