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ultimatesaiyan
11.10.2019 •
Physics
Astudent tries to raise a chain consisting of three identical links. each link has a mass of 300 g . the three-piece chain is connected to a string and then suspended vertically, with the student holding the upper end of the string and pulling upward. because of the student's pull, an upward force of 15.0 n is applied to the chain by the string. use newton's laws to answer the following questions.
find the acceleration of the chain.take the free fall acceleration to be g.find the force exerted by the top link on the middle link.
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Ответ:
a=6.65 m/s²
F(top)=9.96 N
Explanation:
Given that
m= 300 g= 0.3 kg
F= 15 N
Lets acceleration of the chain is a
So from Newton's law
F(net) = m(total) a
F(net) - 3 m g= 3 m a
Here F(net) = F
Take g=9.81 m/s²
So now by putting the values
F - 3 m g= 3 m a
15 - 3 x 0.3 x 9.81 = 3 x 0.3 x a
a=6.85 m/s²
F(top) - 2 m g= 2 m a
F(top)= 2 ma + 2 mg
F(top)=2 x 0.3 (9.81 +6.85 )
F(top)=9.96 N
Ответ:
The time of death was approximately 4 hours before 10:30 AM.
Explanation:
Temperature of the body when discovered by detective at 10:30 AM= 27°C
After discovery, Temperature of the body at 11.30 AM= 24.8°C
Change in time = ΔT = 1 hour
Rate of change of body temperature with respect to time :
Normal body temperature = 37°C
Change in time since death = ΔT'
The time of death was approximately 4 hours before 10:30 AM.