Astudent wants to study the motion of an object that has a constant acceleration. which of the following experiments could the student conduct to provide the best situations in which an object has a constant acceleration? select two answers. a.)release a ball from rest near earth’s surface. b.)release a toy car from rest such that it travels along different looped sections of a track. c.)launch a water-propelled rocket from rest such that it travels into the air and falls back to earth’s surface. d.)release a cart from rest such that it travels down an incline of 40° with respect to the ground.

The correct answer are A and D.

Explanation:

According to the Newton's second law of motion, Acceleration on an object is directly proportional to the net force acting on it. It means that when we introduce force, it introduce acceleration on an object. When an object has constant acceleration, then there must be constant force acting on it. Thus a constant acceleration is required constant force act on it.

A.) Gravitational acceleration is considered constant near the Earth's surface. So, It has constant motion.

B.) The force of a toy car on each looped section of the track has not only the gravitational force, but also the centripetal force. The centripetal acceleration at the top of the loop is different from the centripetal acceleration at the bottom of the loop, so the motion of the toy car along the track is not constant.

C.) The rocket is supported by a water-propelled arm. The forces on the rocket are therefore the water-propelled force and the gravitation. When rocket moves upward, velocity decreases and when rocket moves downward velocity increases. Direction of rocket changes and hence acceleration. Therefore, the acceleration of the rocket is not constant.

D.)The cart is subjected to constant force i.e force of gravity and/or frictional force of the cart by the incline so that the acceleration is steady.

So, Correct answer are A and D.

Answer and Explanation:

If the ant was to crawl 50cm to the right, then come back 30 cm, then the total distance walked would be 80cm.

- Combine 50cm and 30cm to get 80 cm.

For displacement, the answer is 20 cm.

- When calculating displacement, you use the initial (starting) distance. and subtract that from the final distance, giving you the displacement, or the amount traveled from the starting point to the final point if you were to make a straight line from the starting point to end point. (0 to 50, then back 30 the same direction, so subtract 30 from 50 to get 20)

#teamtrees #PAW (Plant And Water)

I hope this helps!